Maths Questions for HTET,KVS Exam : 19th December 2018 (Solutions)

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e HTET Exam 2018, DSSSB ,KVS,STET Exam.
Q1. Simplify: b-[b-(a+b)-{b-(b-a-b)}+2a]
(a) 2b
(b) 1
(c) 0
(d) 3b
Q2. Simplify: (213 x 213 + 187 x 187)
(a) 80338
(b) 80438
(c) 60338
(d) 60438
Q3. What is the remainder, when 4×4 + 10×3 –20×2 + 90 is divided by (x + 2)?
(a) 0
(b) -6
(c) 45
(d) -90
Q4. What will be the value of xy, if x2 + y2 = 45 and x – y = 5? 
(a) 10
(b) 15
(c) 20
(d) 25
Q5. The smallest angle of a triangle is 40° less than the largest angle. If the largest angle is 80°, then find the third angle of the triangle.
(a) 40°
(b) 90°
(c) 80°
(d) 60°
Q6. If the line DE is drawn parallel to the base BC of a triangle ABC by intersecting the other two sides, then which of the following is the CORRECT equation for this case.
(a) AB/AD=AC/EC
(b) AD/AB=DB/EC
(c) AD/DB=EC/AE
(d) AD/DB=AE/EC
Q7. Price of 1 kg of sugar is increased by 30% and the increase is of Rs 48. What is the new price (in Rs) of the sugar per kg?
(a) 178
(b) 160
(c) 208
(d) 216
Q8. The sum of three numbers is 67. If the ratio of the first number to the second number is 3 : 5 and that of the second number to the third numberis 4 : 7, then what is the second number?
(a) 20
(b) 24
(c) 18
(d) 16
Q9. A started a business with the capital of Rs 1800. After 4 months B joined with Rs 3600. 6 months after the business started C joined with Rs 1200.If the total profit earned at the end of the year is Rs 1760, then what is the share (in Rs) of A?
(a) 540
(b) 660
(c) 840
(d) 720
Q10. The average of 8 consecutive integers is 23/2. What is the average of first three integers?
(a) 9
(b) 19/2
(c) 8
(d) 10
Solutions
S1. Ans.(c)
Sol.
Required b – [b – (a + b) – {b – (b – a – b) + 2a]
= b – [ b – a – b – b + b – a – b + 2a
= b – b = 0
S2. Ans.(a)
Sol.
Required = (213² + 187²)
= (213 + 187)² – 2 × 213 × 187
= 160000 – 79662= 80338
S3. Ans.(b)
Sol.
(x + 2) = 0, x= -2 
Putting x = -2 we get
= 4 (-2)4 + 10(-2)³ – 20 (-2)² + 90
= 64 + (-80) – 80 + 90
= -6
S4. Ans.(a)
Sol.
Given,
x² + y² = 45
x -y = 5 
so, (x – y)² = x² + y² – 2xy
⇒ 25 = 45 – 2xy
xy = 10
S5. Ans.(d)
Sol.
Given,
Largest angle = 80°
So, smallest angle is 80° – 40° = 40°
Required third angle = 180° – 80° – 40° = 60°