# Maths Questions for CTET,KVS Exam : 27 october 2018

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB ,KVS,STET Exam.

Q1. What will be average of following numbers?
225, 325, 175, 135, 275

(a) 225
(b)227
(c)220
(d)217

Q2. 24 men can do a task in 12 days. Then 36 men can do same task in how many days ?
(a)18 days
(b) 12 days
(c)8 days
(d) 9 days

Q3. Ram purchase a mobile in Rs. 6600 and sells on 25% profit, what will be selling price of mobile ?
(a) Rs. 8350
(b) Rs.8250
(c) Rs.8150
(d) Rs. 8050

Q4. Find the value of (150 + 0.5 × 40) ÷ 0.8
(a) 210
(b)212.5
(c) 215
(d) 217.5

Q5. Marked price of chair is 3600 Rs. and shopkeeper sold chair in Rs. 3200 Rs. Find discount percent allowed by shopkeeper ?
(a) 12 1/9%
(b) 9 1/9%
(c) 10 1/9%
(d)11 1/9%

Q6. Circumference of a circle is 132 cm, then what will be area of circle ?
(a)1386 sq.cm
(b) 1316 sq.cm
(c) 1456 sq.cm
(d) 1526 sq.cm

Q7. Ankur gets Rs. 1250 interest for 2 year at 10% simple interest rate annually. Find the principal invested by Ankur ?
(a) Rs. 7250
(b) Rs. 5250
(c) Rs. 6000
(d)Rs. 6250

Q8. What will be value of (8.45 × 4 + 112) ?
(a) 130.8
(b) 135.8
(c) 140.8
(d)145.8

Q9. What will be the value of (3.6 × 15 – 2.8 × 5)
(a)45
(b) 30
(c) 35
(d)40

Q10. A and B together can do a piece of work in 9 days. If A does thrice the work of B in a given time, the time A alone will take to finish the work is:
(a) 4 days
(b) 6 days
(c) 8 days
(d) 12 days

SOLUTIONS

S1. Ans.(b)
Sol.
Required average=((225+325+175+135+275))/5
=1135/5=227

S2. Ans.(c)
Sol.
Required days=(M_1×d_1)/M_2
=(24×12)/36
=8 days

S3. Ans.(b)
Sol.
Selling price of mobile
=6600×125/100
=8250 Rs.

S4. Ans.(b)
Sol.
=((150+20))/0.8=212.5

S5. Ans.(d)
Sol.
Discount = 3600 – 3200 = 400 Rs.
Discount%=(MP–SP)/MP×100
=400/3600×100=11 1/9%

S6. Ans.(a)
Sol.
Circumference of circle = 2πr
2πr = 132 cm
r=(132×7)/(22×2)
=21 cm
area=πr^2
=22/7×21×21
=1386 sq.cm

S7. Ans.(d)
Sol.
Principal=(SI×100)/(R×T)
=(1250×100)/(10×2)
=6250 Rs.

S8. Ans.(d)
Sol.
8.45 × 4 + 112 = 145.8

S9. Ans.(d)
Sol.
= 3.6 × 15 – 2.8 × 5
= 54 –14
= 40