Important Mathematics Questions for MPTET 2020 : 22nd January 2020

Maths Questions

Practice Mathematics Questions for MPTET Exam 

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e” Mathematics“.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. With a proper system, Study Notes, Quizzes, Vocabulary one can quiet his/her nerves and exceed expectations in the blink of an eye. So, for this, we are providing you the daily quiz for all teaching exams i.e TET Exam 2020, DSSSBKVSSTET Exam

Q1. 1200 male and 800 females are observed in a task, 48% of the male and 28% of the female qualify in the task. The percentage of total who disqualified in the task?
1200 पुरुष और 800 महिलाएँ एक कार्य करते हैं, 48% पुरुष और 28% महिलाएँ उस कार्य को पूरा करते हैं. कार्य को पूरा ना करने वालों का कुल प्रतिशत बताएं?
(a) 1000
(b) 1200
(c) 1100
(d) 1150

Q2. A child has a certain number of toys of which 8% are found to be broken. He gives 90% of the remainder to his younger brother and still has 66 toys left. How many toys did he original have?
एक बच्चे के पास निश्चित संख्या में खिलौने हैं जिनमें से 8% टूटे हुए हैं. वह शेष के 90% अपने छोटे भाई को देता है और अभी भी उसके 66 खिलौने बाकी हैं. उसके पास कितने खिलौने थे?
(a) 16500
(b) 717
(c) 717.39
(d) 717.50

Q3. By selling a kurti for ₹ 250, a man loses one-sixteenth of what it costs him. Find the cost price of the kurti?
250 की कुर्ती बेचकर, एक आदमी को कुर्ती की लागत के एक-सोलहवें हिस्से की हानि होती है. कुर्ती का लागत मूल्य ज्ञात कीजिये?
(a) 266.6
(b) 266
(c) 260
(d) None of these/ इनमें से कोई नहीं

Q4. Two vessels A and B contain palm oil and mustard oil in ratio 5:3 and 2:3. When these mixtures are mixed to form a new mixture containing half palm oil and half mustard oil, then find the ratio of palm oil and mustard oil in the new vessel?
दो बर्तन A और B में ताड़ का तेल और सरसों का तेल 5: 3 और 2: 3 के अनुपात में है. जब आधा ताड़ का तेल और आधा सरसों का तेल मिलाकर एक नया मिश्रण बनाया जाता है, तो नए बर्तन में तेल और सरसों का अनुपात ज्ञात करें?
(a) 5:4
(b) 4:5
(c) 3:4
(d) 4:3

Q5. In the given figure, AD=DB=DC and ∠DAB=48° find the value of ∠x.
दिए गए चित्र में,  AD=DB=DC और ∠DAB=48° ,तो ∠x का मान ज्ञात करें.

(a) 42°
(b) 48°
(c) 52°
(d) 44°

Q6. If ab = 9 and 3a²b+3ab²+3a+3b = 189, then find the value of a²+b² is
यदि ab = 9 और 3a²b+3ab²+3a+3b = 189, तो a²+b² का मान ज्ञात करें
(a) 21
(b) 22
(c) 21.69
(d) 22.69

Q9. The circumference of the base of right circular cone is 154 cm and height is 21 cm. The volume of the cone is
सम गोलाकार शंकु के आधार की परिधि 154 सेमी और ऊंचाई 21 सेमी है. शंकु का आयतन होगा:
(a) 13205.5
(b) 13205
(c) 13206
(d) 13206.5

(a) 1531.61
(b) 1532
(c) 1530.61
(d) 1531

Solutions

S5. Ans.(a)
Sol. AD=DB=DC (given)
∠DAB= 48° (given)
∠ABD= ∠DAB = 48°
∠DBC= 90°-48°= 42°
∠ACB+∠CAB+∠CBA= 180°
∠x+48°+90° = 180°
∠x+138° = 180°
∠x= 42°

S6. Ans.(c)
Sol. 3a²b+3ab²+3a+3b= 189
3ab(a+b)+3(a+b)= 189
(a+b)(3ab+3)= 189
(a+b)(3×9+3)= 189
(a+b)30 = 189
a+b= 189/30=6.3
(a+b)² = a²+b²+2ab
(6.3)²= a²+b²+2×9
39.69 = a²+b²+18
a²+b² = 21.69

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