Important Maths Questions for UPTET 2019 : 6th January 2020

Maths Questions

UPTET Exam Practice Mathematics Questions

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e Mathematics“.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. With a proper system, Study Notes, Quizzes, Vocabulary one can quiet his/her nerves and exceed expectations in the blink of an eye. So, for this, we are providing you the daily quiz for all teaching exams i.e TET Exam 2019DSSSBKVSSTET Exam.

(a) 7
(b) 4
(c) 6
(d) 0

(a) 92
(b) 91
(c) 90
(d) 84

Q3. What is the value of x°? 
x° का मान ज्ञात कीजिए?

(a)50°
(b) 60°
(c) 65°
(d) 45°

(a) 2704
(b) 52
(c) 2702
(d) 64

Q6. The perimeter of Rhombus is 60cm and the measure of an angle is 60° then the area of it is: 
समचतुर्भुज की परिधि 60 सेमी है और एक कोण का माप 60° है तो इसका क्षेत्रफल होगा:

Q8. A rectangular piece is 40cm long and 30m wide from its four corners, quadrants of radii 3.5m have been cut. The area of remaining part is: 
एक आयताकार टुकड़ा अपने चार कोनों से 40 सेमी लंबा और 30 मीटर चौड़ा है, 3.5 मीटर त्रिज्या का एक खंड इसमें से काट दिया गया है. शेष भाग का क्षेत्रफल होगा:
(a) 1161.5m²
(b) 1161m²
(c) 1161.25m²
(d) 1162m²

Q9. A tin has a square base with side 8cm and height 16cm. Another is cylindrical with radius of its base 7cm and height 18cm. find the difference in their capacities. 
एक टिन का वर्गीय आधार है जिसकी भुजा 8 सेमी और उसकी ऊंचाई 16 सेमी है. एक अन्य का बेलनाकार अधार है जिसकी त्रिज्या 7 सेमी और ऊंचाई 18 सेमी है. उनके आयतन का अंतर बताइए.
(a) 1024cm³
(b) 2772 cm³
(c) 1748 cm³
(d) 1752 cm³

Q10. Find the weight of an iron shell, the external and internal diameters of which are 16cm and 12cm respectively, If 1 cubic cm of iron weights 10 grams. 
यदि 1 घन सेमी लोहे का वजन 10 ग्राम है तो लोहे के खोल का वजन ज्ञात करें, जिसका बाहरी और आंतरिक व्यास क्रमशः 16 सेमी और 12 सेमी है.
(a) 1240 gms
(b) 12403.8 gms
(c) 1240.38 gms
(d) 124038.0 gms

Solutions

S3. Ans. (c)
Sol. ∠LOQ + ∠QOP + ∠POM = 180°
x + 30° + 40 ° + x – 20° = 180°
2x + 50° = 180°
x = 65° 


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