CSIR UGC NET 2020: Exam Pattern and Syllabus

The Council of Scientific and Industrial Research (CSIR) UGC NET 2020 registration has released revised CSIR UGC NET examination date which has been uploaded on official website i.e. 19th, 21st and 26th November, 2020.   All the candidates has started to prepare for the exam. All the candidates has started to prepare for the exam. Here we are going to discuss the syllabus and exam pattern of CSIR UGC NET 2020. It will help you in preparing for the subjects properly.

CSIR-UGC NET June 2020 Revised Examination Date Out : Check Here

CSIR-UGC NET Examination will be going to held for determining the eligibility of Indian Nationals for the award of Junior Research Fellowships (JRF) and for determining eligibility for Lectureship (LS)/Assistant Professorship in certain subject areas falling under the faculty of Science & Technology.i.e.

1. Life Sciences
2. Physical Sciences
3. Chemical Sciences
4. Earth Sciences
5. Mathematical Sciences

NTA CSIR UGC NET Aspirants To Apply Without Category: Check Now

Examination Pattern for CSIR UGC NET 2020:

  • Total Exam Time: 3 hrs
  • Exam type :  multiple choice questions.
  • The Test will consist of three parts i.e. Part A,B,C.
  • Mode of Examination: Computer Based Test (CBT) only.
  • There will be negative marking @ 25% for each wrong answer.
CHEMICAL SCIENCES   Part A Part B Part C Total
Total questions 20 40 60 120
Max No of Questions to attempt 15 35 25 75
Marks for each correct answer 2 2 4 200
Negative marking 0.5 0.5 1
EARTH, ATMOSPHERIC, OCEAN
AND PLANETARY SCIENCES
Part A Part B Part C Total
Total questions 20 50 80 150
Max No of Questions to attempt 15 35 25 75
Marks for each correct answer 2 2 4 200
Negative marking 0.5 0.5 1.32
LIFE SCIENCES Part A Part B Part C Total
Total questions 20 50 75 145
Max No of Questions to attempt 15 35 25 75
Marks for each correct answer 2 2 4 200
Negative marking 0.5 0.5 1
MATHEMATICAL SCIENCES Part A Part B Part C Total
Total questions 20 40 60 120
Max No of Questions to attempt 15 25 20 60
Marks for each correct answer 2 3 4.75 200
Negative marking 0.5 0.75 0
PHYSICAL SCIENCES Part A Part B Part C Total
Total questions 20 25 30 75
Max No of Questions to attempt 15 20 20 55
Marks for each correct answer 2 3.5 5 200
Negative marking 0.5 0.875 1.25

Examination Schedule:

CSIR UGC NET 2020 examination will be going to held on 19th, 21st and 26th November, 2020..The examination schedule is given below:

  • Exam Time : 3 Hrs
  • First Shift Timing : 09.30 am- 12.30 pm
  • Second Shift Timing : 02.30 pm- 5.30 pm

GET FREE STUDY MATERIAL FOR CSIR UGC NET EXAM

CSIR UGC NET 2020 Syllabus:

CHEMICAL SCIENCES

The pattern for the Paper MCQ test shall be as given below:-

1. Paper Type : MCQ test paper
2. Total Marks:200 marks.
3. Exam time: 3 hours.
4. The question paper shall be divided in three parts
5. Negative Marking – 25% for each wrong answer.

Part Detailed Syllabus Total Questions Required to Answer Each Question Marks Total Marks
Part A General Science, Quantitative Reasoning & Analysis and Research Aptitude 20 15 2 30
Part B Subject Concerned 40 35 2 70
Part C Based on scientific concepts and/or application of the scientific concepts. 60 25 4 100
Total 75   200
For Detailed Syllabus Click Here

EARTH, ATMOSPHERIC, OCEAN AND PLANETARY SCIENCES

The pattern for the Paper MCQ test shall be as given below:-

1. Paper Type : MCQ test paper
2. Total Marks:200 marks.
3. Exam time: 3 hours.
4. The question paper shall be divided in three parts
5.Negative Marking For Part A & B- 25% for each wrong answer.
6.Negative Marking For Part C – 33% for each wrong answer.

Part Detailed Syllabus Total Questions Required to Answer Each Question Marks Total Marks
Part A General Science, Quantitative Reasoning & Analysis and Research Aptitude 20 15 2 30
Part B Subject Concerned 50 35 2 70
Part C Based on scientific concepts and/or application of the scientific concepts. 80 25 4 100
Total 75   200
For Detailed Syllabus Click Here

LIFE SCIENCE

The pattern for the Paper MCQ test shall be as given below:-

1. Paper Type : MCQ test paper
2. Total Marks:200 marks.
3. Exam time: 3 hours.
4. The question paper shall be divided in three parts
5.Negative Marking – 25% for each wrong answer.

Part Detailed Syllabus Total Questions Required to Answer Each Question Marks Total Marks
Part A General Science, Quantitative Reasoning & Analysis and Research Aptitude 20 15 2 30
Part B Subject Concerned 50 35 2 70
Part C Based on scientific concepts and/or application of the scientific concepts. 75 25 4 100
Total 75   200
For Detailed Syllabus Click Here

MATHEMATICAL SCIENCES

The pattern for the Paper MCQ test shall be as given below:-

1. Paper Type : MCQ test paper
2. Total Marks:200 marks.
3. Exam time: 3 hours.
4. The question paper shall be divided in three parts
5.Negative Marking for Part A & B – 25% for each wrong answer.No Negative marking for Part ‘C’.

Part Detailed Syllabus Total Questions Required to Answer Each Question Marks Total Marks
Part A General Science, Quantitative Reasoning & Analysis and Research Aptitude 20 15 2 30
Part B Subject Concerned 40 25 2 75
Part C Based on scientific concepts and/or application of the scientific concepts. 60 20 4.75 95
Total 60   200
For Detailed Syllabus Click Here

PHYSICAL SCIENCE

The pattern for the Paper MCQ test shall be as given below:-

1. Paper Type : MCQ test paper
2. Total Marks:200 marks.
3. Exam time: 3 hours.
4. The question paper shall be divided in three parts
5.Negative Marking – 25% for each wrong answer.

Part Detailed Syllabus Total Questions Required to Answer Each Question Marks Total Marks
Part A General Science, Quantitative Reasoning & Analysis and Research Aptitude 20 15 2 30
Part B Part A Core 25 20 3.5 70
Part C Part ‘B’ (Advanced) and Part ‘A’ Based on scientific concepts and/or application of the scientific concepts. 30 20 5 100
Total 55   200
For Detailed Syllabus Click Here

GET FREE STUDY MATERIAL FOR CSIR UGC NET EXAM

CSIR UGC NET 2020 FAQ

Q1. What is CSIR UGC-NET June 2020?

Ans. CSIR UGC-NET is a test being conducted to select the suitable candidates for Assistant Professor and Junior Research fellowship posts in authorized indian college and university for science field..

Q2. Whether the examination will be offline or online?

Ans. This will be a computer-based test and will be conducted through online mode only.

Q3. Is there a criterion for negative marking?

Ans. There will be different criteria for every subjects.

Q4. How to Apply for CSIR UGC NET JUNE Exam 2020?

Ans. The details regarding the submission of application is available on the NTA website i.e. csirnet.nta.nic.in. No other means or mode of application will be accepted.

Q5. When will be the exam conducted?

Ans.The CSIR UGC-NET exam would be held from 19th, 21st and 26th November, 2020.

Q6. What will be the Timing of Examination?

Ans. The examination will be held in two shifts i.e. First Shift: 9.30 am to 12.30 pm Second Shift: 2.30 pm to 05.30 pm. The exam date of CSIR UGC NET i.e. 21st June 2020

CSIR UGC NET 2020 Official Website

CSIR UGC NET June 2020 Notification

GET FREE STUDY MATERIAL FOR CSIR UGC NET EXAM

CSIR UGC NET

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